x^2+8x-1900=0

Solution for x^2+8x-1900=0 equation:

x^2+8x-1900=0

a = 1; b = 8; c = -1900;
Δ = b2-4ac
Δ = 82-4·1·(-1900)
Δ = 7664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7664}=\sqrt{16*479}=\sqrt{16}*\sqrt{479}=4\sqrt{479}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{479}}{2*1}=\frac{-8-4\sqrt{479}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{479}}{2*1}=\frac{-8+4\sqrt{479}}{2}
$